JEE Main 2025 Toppers List: 24 Students Achieve 100 Percentile, Check Full List!
The National Testing Agency (NTA) has declared the JEE Main 2025 Session 2 results for Paper 1 (B.E./B.Tech.) on jeemain.nta.nic.in. The examination, conducted across 531 centres in 300 cities, including 15 international locations, saw participation from over 14.75 lakh unique candidates across both sessions.
For candidates who appeared in both January and April, the best NTA score was considered for ranking.
24 Students Score a Perfect 100 Percentile
This year, 24 students achieved the highest possible NTA score of 100 percentile, highlighting the stiff competition among India’s top engineering aspirants.
Rajasthan led the list with 7 toppers Followed by Maharashtra, Telangana, and Uttar Pradesh (3 each) West Bengal produced 2 toppers Andhra Pradesh, Karnataka, Gujarat, and Delhi also made notable contributionsTwo female candidates stood out:
Devdutta Majhi from West Bengal
Sai Manogna Guthikonda from Andhra Pradesh
Full List of 100 Percentile Scorers (Paper 1 - B.E./B.Tech.)
MD Anas – Rajasthan Ayush Singhal – Rajasthan Archisman Nandy – West Bengal Devdutta Majhi – West Bengal (Female) Aayush Ravi Chaudhari – Maharashtra Lakshya Sharma – Rajasthan Kushagra Gupta – Karnataka Harssh A Gupta – Telangana Aadit Prakash Bhagade – Gujarat Daksh – Delhi Harsh Jha – Delhi Rajit Gupta – Rajasthan Shreyas Lohiya – Uttar Pradesh Saksham Jindal – Rajasthan Saurav – Uttar Pradesh Vangala Ajay Reddy – Telangana Sanidhya Saraf – Maharashtra Vishad Jain – Maharashtra Arnav Singh – Rajasthan Shiven Vikas Toshniwal – Gujarat Kushagra Baingaha – Uttar Pradesh Sai Manogna Guthikonda – Andhra Pradesh (Female) Om Prakash Behera – Rajasthan Bani Brata Majee – TelanganaJEE Advanced 2025 Cut-Off Percentiles (Category-Wise)
The NTA has also released the qualifying percentile scores required to appear for JEE (Advanced) 2025:
General (UR-ALL): 93.1023262 – 100 General-PwBD: 90.0079349 – 93.0950208 EWS: 80.3830119 – 93.0950208 OBC-NCL: 79.4313582 – 93.0950208 SC: 61.1526933 – 93.0950208 ST: 47.9026465 – 93.0950208 Total eligible candidates by category: UR-ALL: 97,321 UR-PwBD: 3,950 EWS: 25,009 OBC-NCL: 67,614 SC: 37,519 ST: 18,823What’s Next?
Students can log in at jeemain.nta.nic.in using their application number and date of birth to:
Check their results Download the official scorecardThe results for Paper 2A (B.Arch.) and 2B (B.Planning) will be announced separately.
Candidates who cleared the cut-off are now eligible for JEE Advanced 2025, the gateway to IIT admissions. It’s time to start preparing for the next big challenge!